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Invoke: Maths Ufies - solution possible?	by poolya	2011-02-17 09:50:11
A solution:	by Ascag	2011-02-17 10:56:10
Method:	by pas51	2011-02-17 11:13:58
a + b + c + d = (a+b) + (c+d) = (a+c) + (b+d) = (a+d) + (b+c) a + b + c + e = (a+b) + (c+e) = (a+c) + (b+e) = (a+e) + (b+c) a + b + d + e = (a+b) + (d+e) = (a+d) + (b+e) = (a+e) + (b+d) a + c + d + e = (a+c) + (d+e) = (a+d) + (c+e) = (a+e) + (c+d) b + c + d + e = (b+c) + (d+e) = (b+d) + (c+e) = (b+e) + (d+e) This yields five equations in five unknowns, which you can then solve (the matrix of coefficients is invertible).
[ Reply ]
To elaborate:	by pas51	2011-02-17 11:58:24
And the sixth value is 1500 - a	by pas51	2011-02-17 12:00:45

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