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Attn: hadji re: how many aces	by hobbs	2006-11-19 12:55:59
I'd still have to see how that was modelled...	by magixtechnica	2006-09-08 00:25:53
Because, take 40 chess pieces and randomly separate half of them. The chances that you get at least 2 knights in one half would (by your model) be some 65%. Does that also mean there would be a 65% chance that there were 2 knights in the OTHER half? Wouldn't you need at least 5 knights to make the math work? o.O I can kinda see that there would be....no, actually I can't see it at all. The chances that half the aces wind up in half the deck, 69% really doesn't make sense to me. You have the OTHER half to consider, along with IT'S chances of keeping half the aces. Oh wait...maybe maybe...no I'll just have to find the right formula and do the actual math when I get off work in the AM.
[ Reply ]
Whoa whoa	by hobbs	2006-09-08 00:45:39
Typo alert	by hobbs	2006-09-08 00:47:06
Yeah, I was just kinda thinking that	by magixtechnica	2006-09-08 00:54:23
The big sigma is basically what my post	by hobbs	2006-09-08 00:59:23
That 65% - 69%	by MatthewDBA	2006-09-08 05:53:15

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