| Invoke and/or ATTN: functional/algebraic UFies |
by ihope127 |
2006-04-12 13:00:52 |
| y = xy
If I'm not mistaken, there is some x such that above (and possibly at) x, the above equation has no solution. What is this value of x? |
|
[ Reply ] |
|
y=1 x=1 ?? (n/t) | by defdood | 2006-04-12 13:03:38 |
|
Yes, I know. I'm asking for the largest possible x | by ihope127 | 2006-04-12 13:08:43 |
|
x = 0 has no such y. | by Nea | 2006-04-12 13:09:31 |
|
Ooops, I missed the "above" part. (n/t) | by Nea | 2006-04-12 13:10:48 |
|
max xth root of x is at e (n/t) | by imperito | 2006-04-12 13:12:02 |
|
Solve for X. | by williamashbless | 2006-04-12 13:17:06 |
|
Meh, I did this backwards, didn't I. Sorry. (n/t) | by williamashbless | 2006-04-12 13:18:10 |
|
Meh. On reflection, I'm hanging up my logic spurs | by williamashbless | 2006-04-12 13:20:38 |
|
but 10^(log(y)/y) is convergent, no? (n/t) | by imperito | 2006-04-12 13:21:19 |
|
Well, I can't solve for y directly BUT... | by williamashbless | 2006-04-12 13:29:11 |
|
like I said, max of xth root of x is at e (n/t) | by imperito | 2006-04-12 13:34:01 |
|
Not that I disagree, but how can you express it... | by williamashbless | 2006-04-12 13:38:43 |
|
start with the original eqn... | by imperito | 2006-04-12 13:48:47 |
|
Glargh, where derivative of x=f(y) is zero. | by williamashbless | 2006-04-12 14:02:29 |
|
Steiner's Problem. | by imperito | 2006-04-12 14:03:54 |
|
Its everywhere! Oh my gods, e is taking over! (n/t) | by williamashbless | 2006-04-12 14:09:00 |
|
It feels that way sometimes | by imperito | 2006-04-12 14:13:32 |
|
I think it should be soluble everywhere | by hobbs | 2006-04-12 13:26:13 |
|
Er, I think you have the base of your log backward (n/t) | by imperito | 2006-04-12 13:29:41 |
|
Sorry, ignore this | by hobbs | 2006-04-12 13:30:16 |
|
eleventy-seven (n/t) | by ag_wyvern | 2006-04-12 13:36:22 |
|
Graphed, and calculated via imperito's trick... | by williamashbless | 2006-04-12 13:42:48 |
|
Or, exactly, e^(1/e), which is about 1.444.... (n/t) | by imperito | 2006-04-12 13:45:29 |
|
Hmm... I graphed the inverse | by maximumbob | 2006-11-19 12:55:59 |
|
So there's no answer to the problem? (n/t) | by ihope127 | 2006-04-12 13:53:36 |
|
No, there is an answer. e. | by williamashbless | 2006-04-12 14:04:42 |
|
Actually, e^(1/e), given that he asked for x | by imperito | 2006-04-12 14:06:13 |
|
Correct. Thanks. (n/t) | by williamashbless | 2006-04-12 14:59:48 |
|
Ah, I see. Thanks. (n/t) | by ihope127 | 2006-04-12 14:34:56 |
|
Hehe..I read that as | by rorajoey | 2006-04-12 14:40:26 |
|
That makes an interesting graph. | by kelli217 | 2006-04-12 14:52:56 |
