The Daily Static
  The Daily Static
UF Archives
Register
UF Membership
Ad Free Site
Postcards
Community

Geekfinder
UFie Gear
Advertise on UF

Forum Rules
& FAQ


Username

Password


Create a New Account

 
 

Back to UserFriendly Strip Comments Index

Math problem by snake2005-05-16 08:48:33
  My solution: by Carciofus 2005-05-16 09:26:36
(made hastily, could be horribly wrong)
Variables:
A - age of mum
V - total value of coins
P - # of pennies
D - # of dimes
Q - # of quartes
N - # of nickels
DEG - degrees between hands.

We know that A = V/6.
As we suppose that Neston's mum is between 20 and 100 years old,
120 <= V <= 600.
Now,
V = P + 10 D + 25 Q + 5 N, and we know that

N = 2 Q
D = 7 P
Q = 5 P

So, we know that V = 246 P.
For V to be between our boundaries, P must be 1 or 2.

But we also know that
DEG = 3 (N + D + Q + P) + 1 - 5 P = 92 P, and as the accident occurred shortly after after four o' clock P = 1 and DEG= 92
(184 would have been far too much).
So, V = 246 and the mum has 41 years.
[ Reply ]
    Argh, I've been outrunned! (n/t) by Carciofus2005-05-16 09:28:07
      And I also forgot the three years too. (n/t) by Carciofus2005-05-16 09:29:56
    Minus three by Control2005-05-16 09:28:52

 

[Todays Cartoon Discussion] [News Index]

Come get yer ARS (Account Registration System) Source Code here!
All images, characters, content and text are copyrighted and trademarks of J.D. Frazer except where other ownership applies. Don't do bad things, we have lawyers.
UserFriendly.Org and its operators are not liable for comments or content posted by its visitors, and will cheerfully assist the lawful authorities in hunting down script-kiddies, spammers and other net scum. And if you're really bad, we'll call your mom. (We're not kidding, we've done it before.)