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Another puzzle by Number_Six2005-03-10 01:43:50
  Spoiler: by Tars_Tarkas2005-03-10 02:05:12
    no by Tobias_E2005-03-10 02:16:30
      My proof goes like this: by Tars_Tarkas 2005-03-10 02:57:38
The largest number of equal digits produced that can be adjectant to a digit is two. One from the left, one from the right. Making it three digits. If there already are more then one digit, the group will be collapsed into a lesser number and the digits will be seperated by a different one...

So if you can only ever have 3 equal digits in a row, the biggest number appearing is 3...

It's really time for me to go to sleep, so I might not have understood your proof correctly, but I guess it sort of says the same as mine (if mine is understandable :)

How about if this was espanded into a 2D matrix?
-><-
Cardinal Tars Tarkas, KSC.
[ Reply ]
        my first argument was wrong, by Tobias_E2005-03-10 04:12:28

 

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