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Another puzzle by Number_Six2005-03-10 01:43:50
  Spoiler: by Tars_Tarkas2005-03-10 02:05:12
    no by Tobias_E 2005-03-10 02:16:30
where shoud it come from ?
a_n times n, a_(n-1) times (n-1), a_(n-2) times (n-2) ...
so for a number greater than three, one would need 4 equal nubers in the row above.Impossible, since every quadrupel always contains n and (n-1)
[ Reply ]
      My proof goes like this: by Tars_Tarkas2005-03-10 02:57:38
        my first argument was wrong, by Tobias_E2005-03-10 04:12:28
      proof correction by Tobias_E2005-03-10 04:07:56

 

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