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I was given a challenge for Perl;	by caffine-iv	2003-01-19 02:34:14
Interesting...	by Spazmatic	2003-01-19 09:40:41
I believe several people are on the right track with answers such as a = a + b; b = a - b; a = a - b; (Yaeger) and Stavros' XOR equivalent, namely in that the key (if such an answer is possible) is that we can use one of the two variables to store the information for both (if they are integers). In fact, I think Yaeger's solution does work for integers (though I'm probably just missing something). The alternative considers that it was never specified that your swap had to be built for a specific ISA. Before computer engineers realized that simple is faster, I seem to recall ISAs that included a 1-cycle swap (though I'm not sure right now). You could check that out for a nice, hacky solution.
[ Reply ]
Stavros' XOR solution doesn't risk overflows	by kahuana	2003-01-19 09:52:32
Overflow isn't really a problem.	by Beorn	2003-01-19 11:37:40

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