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i'm gonna kick myself by nimdokk 2002-06-20 15:30:24
i'm writing up a short perl prog to scan a file and return a pagecount. i specify the file on the commandline. I need to access that filename at the end of the program, what is the default variable for that commandline argument?

#!/usr/bin/perl -w
use strict;
my $pages=0;
foreach (<>) {$pages++ if /\014/;}
print "$ARGV[0] has $pages page(s).\n";

I know that the default variable is not $ARGV[0] but I'm trying to remember what I should include there which will give me the name of the file on which I'm running this prog. Thoughts? I'm reading the Camel book to find the answer at the moment I should know this but simply can't remember at the moment.
[ Reply ]
  further info by nimdokk2002-06-20 15:42:57
    ok by nimdokk2002-06-20 16:06:46
      I've experienced this before by Kickstart2002-06-20 16:58:10
        ok - at least i'm not losing it :) by nimdokk2002-06-20 17:07:34
          nah, you already lost it ;) by ma petite2002-06-20 19:25:59
        It has to dowith the use of <>, not the loop. by inittab2002-06-20 22:43:50
          well by nimdokk2002-06-20 23:23:39
  No! by Naruki2002-06-20 20:15:06

 

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